[Solved] Given the root of a binary tree, return the level order traversal of its nodes’ values. (i.e., from left to right, level by level).

Question

Given the root of a binary tree, return the level order traversal of its nodes’ values. (i.e., from left to right, level by level).

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: [[3],[9,20],[15,7]]

Example 2:

Input: root = [1]
Output: [[1]]

Example 3:

Input: root = []
Output: []

Constraints:

• The number of nodes in the tree is in the range [0, 2000].
• -1000 <= Node.val <= 1000

Python Solution

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def levelOrder(self, root: TreeNode) -> List[List[int]]:
        if root==None:return []
        q = [root]
        res = []
        while q:
            qtemp = []
            r = []
            while q:
                x = q.pop(0)
                r.append(x.val)
                if x.left:qtemp.append(x.left)
                if x.right:qtemp.append(x.right)
            res.append(r)
            q = qtemp
        return res