[Solved] Given an array of string words. Return all strings in words which is substring of another word in any order. String words[i] is substring of words[j], if can be obtained removing some characters to left and/or right side of words[j].

Question

Given an array of string words. Return all strings in words which is substring of another word in any order. 

String words[i] is substring of words[j], if can be obtained removing some characters to left and/or right side of words[j].

Example 1:

Input: words = ["mass","as","hero","superhero"]
Output: ["as","hero"]
Explanation: "as" is substring of "mass" and "hero" is substring of "superhero".
["hero","as"] is also a valid answer.

Example 2:

Input: words = ["leetcode","et","code"]
Output: ["et","code"]
Explanation: "et", "code" are substring of "leetcode".

Example 3:

Input: words = ["blue","green","bu"]
Output: []

Constraints:

• 1 <= words.length <= 100
• 1 <= words[i].length <= 30
• words[i] contains only lowercase English letters.
• It’s guaranteed that words[i] will be unique.

Python Solution

class Solution:
    def stringMatching(self, words: List[str]) -> List[str]:
        words.sort(key=len)
        res=[]
        for i in range(len(words)):
            for j in range(i+1,len(words)):
                if words[i] in words[j]:
                    res.append(words[i])
                    break
        return res