head, the head of a linked list, determine if the linked list has a cycle in it.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the
next pointer. Internally,
pos is used to denote the index of the node that tail’s
next pointer is connected to. Note that
pos is not passed as a parameter.
true if there is a cycle in the linked list. Otherwise, return
Input: head = [3,2,0,-4], pos = 1 Output: true Explanation: There is a cycle in the linked list, where the tail connects to the 1st node (0-indexed).
Input: head = [1,2], pos = 0 Output: true Explanation: There is a cycle in the linked list, where the tail connects to the 0th node.
Input: head = , pos = -1 Output: false Explanation: There is no cycle in the linked list.
- The number of the nodes in the list is in the range
-105 <= Node.val <= 105
-1or a valid index in the linked-list.
Follow up: Can you solve it using
O(1) (i.e. constant) memory?
# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def hasCycle(self, head: ListNode) -> bool: hare = head tortoise = head while hare and hare.next : hare = hare.next.next tortoise = tortoise.next if hare==tortoise: return True return False