# [Solved] You are given an integer array nums with the following properties: nums.length == 2 * n. nums contains n + 1 unique elements. Exactly one element of nums is repeated n times.

## Question

You are given an integer array `nums` with the following properties:

• `nums.length == 2 * n`.
• `nums` contains `n + 1` unique elements.
• Exactly one element of `nums` is repeated `n` times.

Return the element that is repeated `n` times.

Example 1:

```Input: nums = [1,2,3,3]
Output: 3
```

Example 2:

```Input: nums = [2,1,2,5,3,2]
Output: 2
```

Example 3:

```Input: nums = [5,1,5,2,5,3,5,4]
Output: 5
```

Constraints:

• `2 <= n <= 5000`
• `nums.length == 2 * n`
• `0 <= nums[i] <= 104`
• `nums` contains `n + 1` unique elements and one of them is repeated exactly `n` times.

## Python Solution

```class Solution:
def repeatedNTimes(self, A: List[int]) -> int:
for x in A:
if A.count(x)>1:
return x
``` ##### Abhishek Sharma

Started my Data Science journey in my 2nd year of college and since then continuously into it because of the magical powers of ML and continuously doing projects in almost every domain of AI like ML, DL, CV, NLP.

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