## Question

You are given an integer array `nums`

with the following properties:

`nums.length == 2 * n`

.`nums`

contains`n + 1`

**unique**elements.- Exactly one element of
`nums`

is repeated`n`

times.

Return *the element that is repeated *`n`

* times*.

**Example 1:**

Input:nums = [1,2,3,3]Output:3

**Example 2:**

Input:nums = [2,1,2,5,3,2]Output:2

**Example 3:**

Input:nums = [5,1,5,2,5,3,5,4]Output:5

**Constraints:**

`2 <= n <= 5000`

`nums.length == 2 * n`

`0 <= nums[i] <= 10`

^{4}`nums`

contains`n + 1`

**unique**elements and one of them is repeated exactly`n`

times.

## Python Solution

class Solution: def repeatedNTimes(self, A: List[int]) -> int: for x in A: if A.count(x)>1: return x