Given an integer array
nums, return an array
answer such that
answer[i] is equal to the product of all the elements of
The product of any prefix or suffix of
nums is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in
O(n) time and without using the division operation.
Input: nums = [1,2,3,4] Output: [24,12,8,6]
Input: nums = [-1,1,0,-3,3] Output: [0,0,9,0,0]
2 <= nums.length <= 105
-30 <= nums[i] <= 30
- The product of any prefix or suffix of
numsis guaranteed to fit in a 32-bit integer.
Follow up: Can you solve the problem in
O(1) extra space complexity? (The output array does not count as extra space for space complexity analysis.)
class Solution: def productExceptSelf(self, nums: List[int]) -> List[int]: p = 1 n = len(nums) out =  for i in range(n): out.append(p) p = p*nums[i] print(out) p=1 for i in range(n-1,-1,-1): out[i] = out[i]*p p = p*nums[i] return(out)