# [Solved] Given the root of a binary tree and an integer targetSum, return true if the tree has a root-to-leaf path such that adding up all the values along the path equals targetSum. A leaf is a node with no children. ## Question

Given the `root` of a binary tree and an integer `targetSum`, return `true` if the tree has a root-to-leaf path such that adding up all the values along the path equals `targetSum`.

leaf is a node with no children.

Example 1:

```Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22
Output: true
Explanation: The root-to-leaf path with the target sum is shown.
```

Example 2:

```Input: root = [1,2,3], targetSum = 5
Output: false
Explanation: There two root-to-leaf paths in the tree:
(1 --> 2): The sum is 3.
(1 --> 3): The sum is 4.
There is no root-to-leaf path with sum = 5.
```

Example 3:

```Input: root = [], targetSum = 0
Output: false
Explanation: Since the tree is empty, there are no root-to-leaf paths.
```

Constraints:

• The number of nodes in the tree is in the range `[0, 5000]`.
• `-1000 <= Node.val <= 1000`
• `-1000 <= targetSum <= 1000`

## Python Solution

```def dfs(root,curr,target):
global ans
if root==None or ans==True:
return
if curr+root.val==target and root.left==None and root.right==None:
ans = True
dfs(root.left,curr+root.val,target)
dfs(root.right,curr+root.val,target)

class Solution:
def hasPathSum(self, root: TreeNode, targetSum: int) -> bool:
global ans
ans = False
dfs(root,0,targetSum)
return ans```