[Solved] Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Note: A leaf is a node with no children.

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Question

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Note: A leaf is a node with no children.

Example 1:

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Input: root = [3,9,20,null,null,15,7]
Output: 2

Example 2:

Input: root = [2,null,3,null,4,null,5,null,6]
Output: 5

Constraints:

  • The number of nodes in the tree is in the range [0, 105].
  • -1000 <= Node.val <= 1000

Python Solution

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right

def find_min(root,level):
    global m
    if not root: return
    if root.left==None and root.right==None:m = min(m,level+1)
    find_min(root.left,level+1)
    find_min(root.right,level+1)
    
class Solution:
    def minDepth(self, root: TreeNode) -> int:
        global m
        m = 2**31-1
        if root==None:return 0
        find_min(root,0)
        return m

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