# [Solved] Given two integer arrays arr1 and arr2, and the integer d, return the distance value between the two arrays.

## Question

Given two integer arrays `arr1` and `arr2`, and the integer `d`return the distance value between the two arrays.

The distance value is defined as the number of elements `arr1[i]` such that there is not any element `arr2[j]` where `|arr1[i]-arr2[j]| <= d`.

Example 1:

```Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
Output: 2
Explanation:
For arr1[0]=4 we have:
|4-10|=6 > d=2
|4-9|=5 > d=2
|4-1|=3 > d=2
|4-8|=4 > d=2
For arr1[1]=5 we have:
|5-10|=5 > d=2
|5-9|=4 > d=2
|5-1|=4 > d=2
|5-8|=3 > d=2
For arr1[2]=8 we have:
|8-10|=2 <= d=2
|8-9|=1 <= d=2
|8-1|=7 > d=2
|8-8|=0 <= d=2
```

Example 2:

```Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
Output: 2
```

Example 3:

```Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
Output: 1
```

Constraints:

• `1 <= arr1.length, arr2.length <= 500`
• `-1000 <= arr1[i], arr2[j] <= 1000`
• `0 <= d <= 100`

## Python Solution

```class Solution:
def findTheDistanceValue(self, arr1: List[int], arr2: List[int], d: int) -> int:
return sum(all(abs(a - b) > d for b in arr2) for a in arr1)
```