# [Solved] Given an integer n, return a string array answer (1-indexed) where: answer[i] == “FizzBuzz” if i is divisible by 3 and 5. answer[i] == “Fizz” if i is divisible by 3. answer[i] == “Buzz” if i is divisible by 5. answer[i] == i (as a string) if none of the above conditions are true.

## Question

Given an integer `n`, return a string array `answer` (1-indexed) where:

• `answer[i] == "FizzBuzz"` if `i` is divisible by `3` and `5`.
• `answer[i] == "Fizz"` if `i` is divisible by `3`.
• `answer[i] == "Buzz"` if `i` is divisible by `5`.
• `answer[i] == i` (as a string) if none of the above conditions are true.

Example 1:

```Input: n = 3
Output: ["1","2","Fizz"]
```

Example 2:

```Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]
```

Example 3:

```Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
```

Constraints:

• `1 <= n <= 104`

## Python Solution

```class Solution:
def fizzBuzz(self, n: int) -> List[str]:
s=[]
for i in range (1,n+1):
if i%15==0:
s.append("FizzBuzz")
elif i%3==0:
s.append("Fizz")
elif i%5==0:
s.append("Buzz")
else:
s.append(str(i))
return s```