A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array
expected[i] is the expected height of the
ith student in line.
You are given an integer array
heights representing the current order that the students are standing in. Each
heights[i] is the height of the
ith student in line (0-indexed).
Return the number of indices where
heights[i] != expected[i].
Input: heights = [1,1,4,2,1,3] Output: 3 Explanation: heights: [1,1,4,2,1,3] expected: [1,1,1,2,3,4] Indices 2, 4, and 5 do not match.
Input: heights = [5,1,2,3,4] Output: 5 Explanation: heights: [5,1,2,3,4] expected: [1,2,3,4,5] All indices do not match.
Input: heights = [1,2,3,4,5] Output: 0 Explanation: heights: [1,2,3,4,5] expected: [1,2,3,4,5] All indices match.
1 <= heights.length <= 100
1 <= heights[i] <= 100
class Solution: def heightChecker(self, heights: List[int]) -> int: sort_heights = sorted(heights) r=0 for i in range(len(heights)): if heights[i]!=sort_heights[i]: r+=1 return r