# [Solved] A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line.

## Question

A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array `expected` where `expected[i]` is the expected height of the `ith` student in line.

You are given an integer array `heights` representing the current order that the students are standing in. Each `heights[i]` is the height of the `ith` student in line (0-indexed).

Return the number of indices where `heights[i] != expected[i]`.

Example 1:

```Input: heights = [1,1,4,2,1,3]
Output: 3
Explanation:
heights:  [1,1,4,2,1,3]
expected: [1,1,1,2,3,4]
Indices 2, 4, and 5 do not match.
```

Example 2:

```Input: heights = [5,1,2,3,4]
Output: 5
Explanation:
heights:  [5,1,2,3,4]
expected: [1,2,3,4,5]
All indices do not match.
```

Example 3:

```Input: heights = [1,2,3,4,5]
Output: 0
Explanation:
heights:  [1,2,3,4,5]
expected: [1,2,3,4,5]
All indices match.
```

Constraints:

• `1 <= heights.length <= 100`
• `1 <= heights[i] <= 100`

## Python Solution

```class Solution:
def heightChecker(self, heights: List[int]) -> int:
sort_heights = sorted(heights)
r=0
for i in range(len(heights)):
if heights[i]!=sort_heights[i]:
r+=1
return r```