# [Solved] You are given the heads of two sorted linked lists list1 and list2. Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists. Return the head of the merged linked list.

## Question

You are given the heads of two sorted linked lists `list1` and `list2`.

Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.

Example 1:

```Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
```

Example 2:

```Input: list1 = [], list2 = []
Output: []
```

Example 3:

```Input: list1 = [], list2 = [0]
Output: [0]
```

Constraints:

• The number of nodes in both lists is in the range `[0, 50]`.
• `-100 <= Node.val <= 100`
• Both `list1` and `list2` are sorted in non-decreasing order.

## Python Solution

```# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
root = ListNode(-1)
h = root
while l1 or l2:
if l1 and l2:
if l1.val<l2.val:
root.next = l1
root = root.next
l1=l1.next
else:
root.next=l2
root = root.next
l2=l2.next

elif l1:
root.next = l1
break

elif l2:
root.next = l2
break
return h.next
```