# [Solved] Given an integer x, return true if x is palindrome integer. An integer is a palindrome when it reads the same backward as forward. ## Question

Given an integer `x`, return `true` if `x` is palindrome integer.

An integer is a palindrome when it reads the same backward as forward.

• For example, `121` is a palindrome while `123` is not.

Example 1:

```Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
```

Example 2:

```Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
```

Example 3:

```Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
```

Constraints:

• `-231 <= x <= 231 - 1`

Follow up: Could you solve it without converting the integer to a string?

## Python Solution

```class Solution:
def isPalindrome(self, x: int) -> bool:
def reverse(n):
rev=0
while n!=0:
rem = n%10
rev=rev*10+rem
n=n//10
return rev

if x<0:
return False
else:
return x==reverse(x)
```