# [Solved] Given an integer n, return true if it is a power of two. Otherwise, return false. An integer n is a power of two, if there exists an integer x such that n == 2x.

## Question

Given an integer `n`, return `true` if it is a power of two. Otherwise, return `false`.

An integer `n` is a power of two, if there exists an integer `x` such that `n == 2x`.

Example 1:

```Input: n = 1
Output: true
Explanation: 20 = 1
```

Example 2:

```Input: n = 16
Output: true
Explanation: 24 = 16
```

Example 3:

```Input: n = 3
Output: false
```

Constraints:

• `-231 <= n <= 231 - 1`

Follow up: Could you solve it without loops/recursion?

## Python Solution

```class Solution:
def isPowerOfTwo(self, n: int) -> bool:
if n<=0:
return False
while n>0:
if n==1:
return True
elif n%2==0:
n/=2
else:
return False
``` ##### Abhishek Sharma

Started my Data Science journey in my 2nd year of college and since then continuously into it because of the magical powers of ML and continuously doing projects in almost every domain of AI like ML, DL, CV, NLP.

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