[Solved] Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

Question

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000

Example 2:

Input: x = 2.10000, n = 3
Output: 9.26100

Example 3:

Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25

Constraints:

  • -100.0 < x < 100.0
  • -231 <= n <= 231-1
  • -104 <= xn <= 104

Python Solution

class Solution:
    def myPow(self, x: float, n: int) -> float:
        if n==0:
            return 1
        
        if n==1:
            return x
        
        if x==0:
            return 0
        
        if x==1:
            return 1
        
        if n<0:
            return 1/self.myPow(x,-n)
        
        if n%2:
            return x*self.myPow(x,n-1)
        else:
            return self.myPow(x*x, n//2)
Abhishek Sharma
Abhishek Sharma

Started my Data Science journey in my 2nd year of college and since then continuously into it because of the magical powers of ML and continuously doing projects in almost every domain of AI like ML, DL, CV, NLP.

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