# [Solved] Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 – 1], then return 0. Assume the environment does not allow you to store 64-bit integers (signed or unsigned). ## Question

Given a signed 32-bit integer `x`, return `x` with its digits reversed. If reversing `x` causes the value to go outside the signed 32-bit integer range `[-231, 231 - 1]`, then return `0`.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

```Input: x = 123
Output: 321
```

Example 2:

```Input: x = -123
Output: -321
```

Example 3:

```Input: x = 120
Output: 21
```

Constraints:

• `-231 <= x <= 231 - 1`

## Python Solution

```class Solution:
def reverse(self, x: int) -> int:
rev=0
n=0
if x<0:
n=1
x=abs(x)
while x>0:
rem = x%10
rev = rev*10 + rem
x = x//10

if rev in range(-2**31,2**31):
if n==1:
return -1*rev
else:
return rev
else:
return 0```
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