Question
Given a non-negative integer x
, compute and return the square root of x
.
Since the return type is an integer, the decimal digits are truncated, and only the integer part of the result is returned.
Note: You are not allowed to use any built-in exponent function or operator, such as pow(x, 0.5)
or x ** 0.5
.
Example 1:
Input: x = 4 Output: 2
Example 2:
Input: x = 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
Constraints:
0 <= x <= 231 - 1
Python Solution
class Solution: def mySqrt(self, x: int) -> int: left, right = 0, x res = 0 while left <= right: mid = (right + left) // 2 if mid * mid <= x: res = mid left = mid + 1 else: right = mid - 1 return res