## Question

Given an integer number `n`

, return the difference between the product of its digits and the sum of its digits.

**Example 1:**

Input:n = 234Output:15Explanation:Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15

**Example 2:**

Input:n = 4421Output:21Explanation:Product of digits = 4 * 4 * 2 * 1 = 32 Sum of digits = 4 + 4 + 2 + 1 = 11 Result = 32 - 11 = 21

**Constraints:**

`1 <= n <= 10^5`

## Python Solution

class Solution: def subtractProductAndSum(self, n: int) -> int: s=0 m=1 for i in str(n): m*=int(i) s+=int(i) return m-s